document.write( "Question 135159: \r
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\n" ); document.write( "\n" ); document.write( "(x+5)^2/3=4\r
\n" ); document.write( "\n" ); document.write( "i don't have a clue.
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Algebra.Com's Answer #98994 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
(x+5)^2/3=4
\n" ); document.write( "the exponent (^2/3) is another way of representin the cuberoot of the square of the term (x+5).
\n" ); document.write( "cubert(x+5)^2=4
\n" ); document.write( "now if we cube each side of the equation we get:
\n" ); document.write( "(x+5)^2=4^3
\n" ); document.write( "x^2+10x+25=64
\n" ); document.write( "x^2+10x+25-64=0
\n" ); document.write( "x^2+10x-39=0
\n" ); document.write( "(x+13)(x-3)=0
\n" ); document.write( "x+13=0
\n" ); document.write( "x=-13 answer.
\n" ); document.write( "x-3=0
\n" ); document.write( "x=3 answer.
\n" ); document.write( "proof:
\n" ); document.write( "cubert(3+5)^2=4
\n" ); document.write( "cubert(8^2)=4
\n" ); document.write( "cubert64=4
\n" ); document.write( "4=4\r
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