document.write( "Question 135159: \r
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document.write( "(x+5)^2/3=4\r
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document.write( "i don't have a clue. \n" );
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Algebra.Com's Answer #98994 by checkley77(12844) ![]() You can put this solution on YOUR website! (x+5)^2/3=4 \n" ); document.write( "the exponent (^2/3) is another way of representin the cuberoot of the square of the term (x+5). \n" ); document.write( "cubert(x+5)^2=4 \n" ); document.write( "now if we cube each side of the equation we get: \n" ); document.write( "(x+5)^2=4^3 \n" ); document.write( "x^2+10x+25=64 \n" ); document.write( "x^2+10x+25-64=0 \n" ); document.write( "x^2+10x-39=0 \n" ); document.write( "(x+13)(x-3)=0 \n" ); document.write( "x+13=0 \n" ); document.write( "x=-13 answer. \n" ); document.write( "x-3=0 \n" ); document.write( "x=3 answer. \n" ); document.write( "proof: \n" ); document.write( "cubert(3+5)^2=4 \n" ); document.write( "cubert(8^2)=4 \n" ); document.write( "cubert64=4 \n" ); document.write( "4=4\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |