document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=135161>Question 135161</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve: 4^(1-x)=3*5^x <BR>\n" );
document.write( "I hope someone can help me, I have been trying to figure this one out for a while:( This is what I got : 4/3^x=3*5<BR>\n" );
document.write( "                             4/3=(4*5)^x<BR>\n" );
document.write( "                            x=log(4/3)/log20 <BR>\n" );
document.write( "                           x=0.096... But my teacher marked it wrong :( </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #98993 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=98993\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve: 4^(1-x)=3*5^x <BR>\n" );
document.write( "Take the log of both sides to get:<BR>\n" );
document.write( "(1-x)log4 = log3 + xlog5<BR>\n" );
document.write( "log4-xlog4 = log3 + xlog5<BR>\n" );
document.write( "x(log4-log5) = log2-log4<BR>\n" );
document.write( "x(log(4/5)) = log(1/2)<BR>\n" );
document.write( "x = [log(1/2)]/[log(4/5)]<BR>\n" );
document.write( "x = 3.1063<BR>\n" );
document.write( "=================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );