document.write( "Question 135098: please, I need your help in thi. it is urgent.\r
\n" ); document.write( "\n" ); document.write( "I really don't know the range of f(x)= x^2/3 + 2\r
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Algebra.Com's Answer #98931 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
really don't know the range of f(x)= x^2/3 + 2
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\n" ); document.write( "The range is all values of y:
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\n" ); document.write( "y = f(x)
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\n" ); document.write( "y = x^(2/3) + 2
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\n" ); document.write( "Note that x is squared, therefore for any value of x, x^(2/3) will always => 0
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\n" ); document.write( "Note also that the constant is 2
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\n" ); document.write( "Therefore the range will be all real numbers => +2
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