document.write( "Question 135098: please, I need your help in thi. it is urgent.\r
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document.write( "I really don't know the range of f(x)= x^2/3 + 2\r
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Algebra.Com's Answer #98931 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! really don't know the range of f(x)= x^2/3 + 2 \n" ); document.write( ": \n" ); document.write( "The range is all values of y: \n" ); document.write( ": \n" ); document.write( "y = f(x) \n" ); document.write( ": \n" ); document.write( "y = x^(2/3) + 2 \n" ); document.write( ": \n" ); document.write( "Note that x is squared, therefore for any value of x, x^(2/3) will always => 0 \n" ); document.write( ": \n" ); document.write( "Note also that the constant is 2 \n" ); document.write( ": \n" ); document.write( "Therefore the range will be all real numbers => +2 \n" ); document.write( " |