document.write( "Question 135070: If Steven can mix 20 drinks in 5 minutes, Sue can mix 20 drinks in 10 minutes, and Jack can mix 20 drinks in 15 minutes, how much time will it take all 3 of them working together to mix the 20 drinks? \n" ); document.write( "
Algebra.Com's Answer #98915 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! If Steven can mix 20 drinks in 5 minutes, Sue can mix 20 drinks in 10 minutes, and Jack can mix 20 drinks in 15 minutes, how much time will it take all 3 of them working together to mix the 20 drinks? \n" ); document.write( ": \n" ); document.write( "Here is another method, which I think is simpler. \n" ); document.write( ": \n" ); document.write( "Let t = time (in min) required when they all work together \n" ); document.write( ": \n" ); document.write( "Let the completed job = 1; (the mixing of 20 drinks) \n" ); document.write( ": \n" ); document.write( "A simple shared work equation: \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Multiplying the equation by 30 gets rid of the denominators: \n" ); document.write( "6t + 3t + 2t = 30 \n" ); document.write( ": \n" ); document.write( "11t = 20 \n" ); document.write( ": \n" ); document.write( "t = \n" ); document.write( ": \n" ); document.write( "t = 2.727 min \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check: \n" ); document.write( " \n" ); document.write( ".545 + .272 + .182 = .99 ~ 1 \n" ); document.write( ": \n" ); document.write( "Sorry I got my numbers wrong the 1st time. \n" ); document.write( " |