document.write( "Question 135070: If Steven can mix 20 drinks in 5 minutes, Sue can mix 20 drinks in 10 minutes, and Jack can mix 20 drinks in 15 minutes, how much time will it take all 3 of them working together to mix the 20 drinks? \n" ); document.write( "
Algebra.Com's Answer #98915 by ankor@dixie-net.com(22740)\"\" \"About 
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If Steven can mix 20 drinks in 5 minutes, Sue can mix 20 drinks in 10 minutes, and Jack can mix 20 drinks in 15 minutes, how much time will it take all 3 of them working together to mix the 20 drinks?
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\n" ); document.write( "Here is another method, which I think is simpler.
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\n" ); document.write( "Let t = time (in min) required when they all work together
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\n" ); document.write( "Let the completed job = 1; (the mixing of 20 drinks)
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\n" ); document.write( "A simple shared work equation:
\n" ); document.write( "\"t%2F5\" + \"t%2F10\" + \"t%2F15\" = 1
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\n" ); document.write( "Multiplying the equation by 30 gets rid of the denominators:
\n" ); document.write( "6t + 3t + 2t = 30
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\n" ); document.write( "11t = 20
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\n" ); document.write( "t = \"30%2F11\"
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\n" ); document.write( "t = 2.727 min
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\n" ); document.write( "Check:
\n" ); document.write( "\"2.727%2F5\" + \"2.727%2F10\" + \"2.727%2F15\" =
\n" ); document.write( ".545 + .272 + .182 = .99 ~ 1
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\n" ); document.write( "Sorry I got my numbers wrong the 1st time.
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