document.write( "Question 135065: I do not know how to solve this.
\n" ); document.write( "Find three consecutive even intergers such that four times the middle interger is equal to two less than the sum of the first and third intgers. \r
\n" ); document.write( "\n" ); document.write( "Equation:?\r
\n" ); document.write( "\n" ); document.write( "Set up
\n" ); document.write( "1st no. = n
\n" ); document.write( "2nd no. = n+2
\n" ); document.write( "3rd no n+4\r
\n" ); document.write( "\n" ); document.write( "I have no clue how to solve this.
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Algebra.Com's Answer #98892 by vleith(2983)\"\" \"About 
You can put this solution on YOUR website!
You have more than a clue. Don't fret, You are part way there already.\r
\n" ); document.write( "\n" ); document.write( "Your solution uses the number n. But there is nothing that ensures that 'n' is even. So let's use a different set of numbers.
\n" ); document.write( "Let's assume n is even, if so, then n/2 is still an integer.
\n" ); document.write( "Our three numbers will be n/2, (n+4)/2 and (n+8)/2\r
\n" ); document.write( "\n" ); document.write( "Add in one more given \" four times the middle integer is equal to two less than the sum of the first and third integers.\"\r
\n" ); document.write( "\n" ); document.write( "so \"4%2A%28%28n%2B4%29%2F2%29+=+%28%28n%2F2+%2B+%28n%2B8%29%2F2%29%29+-+2+%29\"
\n" ); document.write( "Left left side is four times the middle number. The right side is the (sum of the first and third) minus 2\r
\n" ); document.write( "\n" ); document.write( "Now solve\r
\n" ); document.write( "\n" ); document.write( "\"4%2A%28%28n%2B4%29%2F2%29+=+%28%28n%2F2+%2B+%28n%2B8%29%2F2%29%29+-+2+%29\"
\n" ); document.write( "\"4%2A%28n%2B4%29+=+%28%28n+%2B+%28n%2B8%29%29+-+4+%29\"
\n" ); document.write( "\"4n%2B16%29+=+%282n+%2B+8+-+4+%29\"
\n" ); document.write( "\"4n%2B16%29+=+2n+%2B+4+\"
\n" ); document.write( "\"2n+=+-12+\"
\n" ); document.write( "n = -6\r
\n" ); document.write( "\n" ); document.write( "Check : is 4(-4) = (-6 + -2) - 2?
\n" ); document.write( "Nope, so I think there is not a solution to this one
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