document.write( "Question 20529: Claire has a small personal business making scented candles.
\n" ); document.write( "Her startup costs are $200. Her cost to make each cangle is
\n" ); document.write( "$1.50. She sells each candle for $4.00. Use a system of
\n" ); document.write( "equations to determine the number of candles she must sell
\n" ); document.write( "to break even. (Write one equation for her prodction costs
\n" ); document.write( "and one for her sales revenue.)=
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Algebra.Com's Answer #9886 by mmm4444bot(95)\"\" \"About 
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Hello There:\r
\n" ); document.write( "\n" ); document.write( "Let x = the number of candles produced and sold.\r
\n" ); document.write( "\n" ); document.write( "The costs are modeled by this equation:\r
\n" ); document.write( "\n" ); document.write( "C = 200 + 1.5*x\r
\n" ); document.write( "\n" ); document.write( "because each x costs $1.50, and there is the startup costs (which is fixed one time only) of $200.\r
\n" ); document.write( "\n" ); document.write( "The revenue is modeled by this equation:\r
\n" ); document.write( "\n" ); document.write( "R = 4*x\r
\n" ); document.write( "\n" ); document.write( "because they collect $4 for each x.\r
\n" ); document.write( "\n" ); document.write( "To break even means that the costs equal the revenue (i.e., there is no profit, but there is no loss either).\r
\n" ); document.write( "\n" ); document.write( "We find this number of candles by setting the costs equal to the revenue.\r
\n" ); document.write( "\n" ); document.write( "200 + 1.5*x = 4*x\r
\n" ); document.write( "\n" ); document.write( "Subtract 1.5*x from both sides so that we can combine the x-terms together on the right side.\r
\n" ); document.write( "\n" ); document.write( "200 = 4*x - 1.5*x\r
\n" ); document.write( "\n" ); document.write( "200 = 2.5*x\r
\n" ); document.write( "\n" ); document.write( "Solve for x by dividing both sides by 2.5:\r
\n" ); document.write( "\n" ); document.write( "x = 200/2.5\r
\n" ); document.write( "\n" ); document.write( "x = 80\r
\n" ); document.write( "\n" ); document.write( "~ Mark
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