document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=134998>Question 134998</A>: <I><SPAN STYLE=\"word-break: break-all;\"> More word problems.<BR>\n" );
document.write( "The average value of a certain type of automobile was $15,780 in 1992 and depreciated to $6720 in 1996. Let y be the average value of the automobe in the year x, where x=0 represents 1992. Write a linear equation that models the value of the automobile in terms of the year x. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #98855 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=98855\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The average value of a certain type of automobile was $15,780 in 1992 and depreciated to $6720 in 1996. Let y be the average value of the automobe in the year x, where x=0 represents 1992. Write a linear equation that models the value of the automobile in terms of the year x.<BR>\n" );
document.write( "-----------------<BR>\n" );
document.write( "y-intercept = 15,780<BR>\n" );
document.write( "-----------<BR>\n" );
document.write( "slope = (6720-15780)/(1996-1992) = -2265<BR>\n" );
document.write( "----------------<BR>\n" );
document.write( "EQUATION:<BR>\n" );
document.write( "y = -2265x + 15780<BR>\n" );
document.write( "======================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );