document.write( "Question 134938This question is from textbook Algebra Structure and Method
\n" ); document.write( ": I have been struggling on this math problem for awhile now and I was wondering if anyone could help me? It has a picture with it, so I am going to describe the picture as best as I can!! I would deeply appreciate it!! Please and Thank you!!\r
\n" ); document.write( "\n" ); document.write( "Area Problems
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\n" ); document.write( "The area of a circle of a radius r is given by the formula a=pier^2. Use this fact to find a formula for the shaded area in the figure below.
\n" ); document.write( "The figure is a big circle with a small circle in side of it. The radius is inside the small circle. The width is in the big circle. radius=r and width=w
\n" ); document.write( "The shaded region is the big circle.\r
\n" ); document.write( "\n" ); document.write( "I don't know if this helps at all, but I am hoping someone could help me!!
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Algebra.Com's Answer #98845 by rajagopalan(174)\"\" \"About 
You can put this solution on YOUR website!
It seems the problem of finding area of shaded portion of circle in a circle.
\n" ); document.write( "Area of big circle =pi(w)^2/4
\n" ); document.write( "Area of small circle=pi(r)^2
\n" ); document.write( "Shaded area = Area of Big Circle - area of small circle
\n" ); document.write( "=pi(w/2)^2-(r)^2)
\n" ); document.write( "=pi(w/2 + r)(w/2 - r)
\n" ); document.write( "in a nut shell pi times product of sum and difference of radii
\n" ); document.write( "Answer:
\n" ); document.write( "Shaded Area =pi(w/2 + r)(w/2 - r)
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