document.write( "Question 134933: Determine whether the following pairs are invers of eachother\r
\n" );
document.write( "\n" );
document.write( "a. f9x0=8x-7 and g(x)=x+8/7\r
\n" );
document.write( "\n" );
document.write( "b. f(x)= 1/x and g(x)= 1/x\r
\n" );
document.write( "\n" );
document.write( "c. f(x)= 2x+3/x-1 and g(x)=x+3/x-2 \n" );
document.write( "
Algebra.Com's Answer #98823 by stanbon(75887) ![]() You can put this solution on YOUR website! Determine whether the following pairs are invers of eachother\r \n" ); document.write( "\n" ); document.write( "a. f(x)=8x-7 and g(x)=(x+8)/7 \n" ); document.write( "fog(x)= f[(x+8)/7] = 8[(x+8)/7] \n" ); document.write( "They are not inverse as the result has to be \"x\" if f and g are inverse. \n" ); document.write( "-----------------------------------------\r \n" ); document.write( "\n" ); document.write( "b. f(x)= 1/x and g(x)= 1/x \n" ); document.write( "fog(x) = f(1/x) = 1/(1/x) = x \n" ); document.write( "gof(x) = g(1/x) = 1/(1/x) = x \n" ); document.write( "There are inverse to one another. \n" ); document.write( "------------------------------------ \n" ); document.write( "c. f(x)= 2x+3/x-1 and g(x)=x+3/x-2 \n" ); document.write( "fog(x) = f[(x+3)/(x-2)] = [2[(x+3)/(x-2)]+3]/[(x+3)/(x-2)-1] \n" ); document.write( "= [(2x+6)+3(x-2)]/(x-2) / [(x+3 -x+2]/(x-2)\r \n" ); document.write( "\n" ); document.write( "= [2x+6 + 3x-6]/[5]\r \n" ); document.write( "\n" ); document.write( "= [5x]/5 = x \n" ); document.write( "--------------------- \n" ); document.write( "If you have the patience, check gof(x) to see if you \"x\" \n" ); document.write( "If you do, f and g are inverse. \n" ); document.write( "============================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |