document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=134929>Question 134929</A>: <I><SPAN STYLE=\"word-break: break-all;\"> write a quadratic equation that describes the area of a rectangle whose perimeter is 24 feet. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #98811 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=98811\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> write a quadratic equation that describes the area of a rectangle whose perimeter is 24 feet.<BR>\n" );
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document.write( "2L + 2W = 24<BR>\n" );
document.write( "Simplify<BR>\n" );
document.write( "L + W = 12<BR>\n" );
document.write( "L = (12 - W)<BR>\n" );
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document.write( "Area = L*W<BR>\n" );
document.write( "Substitute (12-W) for L<BR>\n" );
document.write( "A = (12-W)*W<BR>\n" );
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document.write( "A = -W^2 + 12W: a quadratic equation describing the area </SPAN>\n" );
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