document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=134924>Question 134924</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Ok this one has completely stumped me:  i am only coming up with two answers but the answer in the back of the book says three different answers: HELP!!<BR>\n" );
document.write( "4x^3+24x^2+12x-40=0;-2  The problem says use synthetic division to show the number given to the right of the equation is in fact a solution and then solve the polynomial.  \r<BR>\n" );
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document.write( "Thank you in advance!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #98789 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=98789\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> since -2 is a zero (root), x+2 is a factor\r<BR>\n" );
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document.write( "4x^3+24x^2+12x-40=0 __ (x+2)(4x^2+16x-20)=0\r<BR>\n" );
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document.write( "dividing by 4 and factoring __ (x+2)(x+5)(x-1)=0 </SPAN>\n" );
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