document.write( "Question 134911: Can you please help me?
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document.write( "find the variation equation for the variation statement.\r
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document.write( "z varies jointly as y and the cube of x; z=160 when x=2 and y=-5\r
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document.write( "Thanks again \n" );
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Algebra.Com's Answer #98779 by nycsharkman(136)![]() ![]() ![]() You can put this solution on YOUR website! This question is asking for the EQUATION and thus it is NOT asking you to solve for any letters in particular.\r \n" ); document.write( "\n" ); document.write( "If z varies jointly as y and the cube of x, then we have this equation:\r \n" ); document.write( "\n" ); document.write( "z = k(x^3)(y), where k is the constant of variation.\r \n" ); document.write( "\n" ); document.write( "Let plug the given numbers WITHOUT solving for k.\r \n" ); document.write( "\n" ); document.write( "160 = k(2)^3(-5)\r \n" ); document.write( "\n" ); document.write( "160 = k(8)(-5)\r \n" ); document.write( "\n" ); document.write( "160 = -40k\r \n" ); document.write( "\n" ); document.write( "================================================== \n" ); document.write( "You said:\r \n" ); document.write( "\n" ); document.write( "\"I was looking for: y=-4xy^3, y=4x^3y, y=4xy^3, y=-4x^3y\"\r \n" ); document.write( "\n" ); document.write( "I said: \n" ); document.write( " \n" ); document.write( "In the question, you did not indicate that the constant of variation, which is k needed to be found. \n" ); document.write( " \n" ); document.write( "I found this equation: \n" ); document.write( " \n" ); document.write( "160 = -40k \n" ); document.write( " \n" ); document.write( "Divide both sides by -40 and k = -4. \n" ); document.write( " \n" ); document.write( "Then your equation and answer is: \n" ); document.write( " \n" ); document.write( "z = -4x^3y \n" ); document.write( " \n" ); document.write( "It cannot be y = -4x^3y because z varies jointly as y and the cube of x. \n" ); document.write( " \n" ); document.write( "In other words, if your question has a letter z, then z MUST appear or be part of your equation. \n" ); document.write( " \n" ); document.write( " |