document.write( "Question 134877This question is from textbook
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\n" ); document.write( "\n" ); document.write( "3x^3+81
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Algebra.Com's Answer #98772 by nycsharkman(136)\"\" \"About 
You can put this solution on YOUR website!
Factor:\r
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\n" ); document.write( "\n" ); document.write( "We have the sum of cubes.\r
\n" ); document.write( "\n" ); document.write( "We use this formula:\r
\n" ); document.write( "\n" ); document.write( "x^3 + y^3 = (x+y)(x^2-xy+y^2)\r
\n" ); document.write( "\n" ); document.write( "First thing you want to do is factor out 3.\r
\n" ); document.write( "\n" ); document.write( "3(x^3 + 27)...In other words, 3x^3 divided by 3 = x^3 and 81 divided by 3 = 27 (in case you are wondering where those numbers came from).\r
\n" ); document.write( "\n" ); document.write( "We now factor the sum of cubes listed in the parentheses.\r
\n" ); document.write( "\n" ); document.write( "Write 27 using base 3.\r
\n" ); document.write( "\n" ); document.write( "3^3 = 27\r
\n" ); document.write( "\n" ); document.write( "We now have:\r
\n" ); document.write( "\n" ); document.write( "3(x^3 + 3^3)\r
\n" ); document.write( "\n" ); document.write( "Base x and 3 = base x and y in the above formula.\r
\n" ); document.write( "\n" ); document.write( "Here comes the easy part.\r
\n" ); document.write( "\n" ); document.write( "We plug and chug.\r
\n" ); document.write( "\n" ); document.write( "x^3 + y^3 = (x+y)(x^2-xy+y^2)....This is the formula for the sum of cubes.\r
\n" ); document.write( "\n" ); document.write( "3(x^3 + 3^3) = 3(x + 3)(x^2 - 3y + 3^2)\r
\n" ); document.write( "\n" ); document.write( "3(x^3 + 3^3) = 3(x + 3)(x^2 - 3y + 9)\r
\n" ); document.write( "\n" ); document.write( "The original question actually breaks into 3 factors:\r
\n" ); document.write( "\n" ); document.write( "3, (x + 3) and (x^2 - 3y + 9)\r
\n" ); document.write( "\n" ); document.write( "Final answer: \r
\n" ); document.write( "\n" ); document.write( "3(x + 3)(x^2 - 3y + 9)\r
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