document.write( "Question 134905: Please help me, I am lost.
\n" ); document.write( "complete the square and write the equation in standard form. Then give the center and radius of the circle:
\n" ); document.write( "x^2+y^2-2x-4y-4=0\r
\n" ); document.write( "\n" ); document.write( "Thank you so much
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Algebra.Com's Answer #98771 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
Step 1: Set the constant term on the right side of the equation:\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2By%5E2-2x-4y=4\"\r
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\n" ); document.write( "\n" ); document.write( "Step 2: Rearrange the terms, put the x terms together and the y terms together:\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-2x%2By%5E2-4y=4\"\r
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\n" ); document.write( "\n" ); document.write( "Step 3: Divide the coefficient on the x term by 2, and then square the result:\r
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\n" ); document.write( "\n" ); document.write( "\"%28%28-2%29%2F2%29%5E2=1\"\r
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\n" ); document.write( "\n" ); document.write( "Step 4: Add this value to both sides of the equation:\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-2x%2B1%2By%5E2-4y=4%2B1\"\r
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\n" ); document.write( "\n" ); document.write( "Step 5: Repeat steps 3 and 4 using the coefficient on the y term:\r
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\n" ); document.write( "\n" ); document.write( "\"%28%28-4%29%2F2%29%5E2=4\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-2x%2B1%2By%5E2-4y%2B4=4%2B1%2B4\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-2x%2B1\" is a perfect square, so \"x%5E2-2x%2B1=%28x-1%29%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"y%5E2-4y%2B4\" is a perfect square, so \"y%5E2-4y%2B4=%28y-2%29%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "Step 6: Using this information, re-write the equation:\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-1%29%5E2%2B%28y-2%29%5E2=9\"\r
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\n" ); document.write( "\n" ); document.write( "This is now in the standard form of an equation of a circle with center at (h,k) and radius r, namely \"%28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "Step 7: You can now tell by inspection that the x-coordinate of the center is 1, the y-coordinate of the center is 2, and the radius is \"sqrt%289%29=3\".\r
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\n" ); document.write( "\n" ); document.write( "C(1,2), r = 3
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