document.write( "Question 134904: This problem I don't understand due to the fact that it gives me only a few numbers to work with.\r
\n" ); document.write( "\n" ); document.write( "Given: \"log+%284%2C+3%29=+0.7925\" and \"log+%284%2C+5%29=+1.160\"\r
\n" ); document.write( "\n" ); document.write( "The question: \"log+%284%2C+12%2F5%29\" \r
\n" ); document.write( "\n" ); document.write( "The problem is that I get to where I split up the 12 to 3*4, but that is as far as I got.
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Algebra.Com's Answer #98763 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
Remember that \"log%28b%2Cx%29%2Blog%28b%2Cy%29=log%28b%2C%28x%2Ay%29%29\" and that since \"log%28b%2Cx%29=y\"=>\"b%5Ey=x\", \"log%28b%2Cb%29=1\".\r
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\n" ); document.write( "\n" ); document.write( "So: \"log%284%2C12%29=log%284%2C%283%2A4%29%29=log%284%2C3%29%2Blog%284%2C4%29=log%284%2C3%29%2B1\"\r
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\n" ); document.write( "\n" ); document.write( "That and remembering the fact that \"log%28b%2Cx%29-log%28b%2Cy%29=log%28b%2C%28x%2Fy%29%29\" should get you through the rest of this one.
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