document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=134894>Question 134894</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If I have to Let ABC have vertices a(-6,3),B(-1,-4), and C(3,-5).Give the coordinates of the vertices of the image after the specified transformation.\r<BR>\n" );
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document.write( "17. Reflection in the x-axis\r<BR>\n" );
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document.write( "How does that work? Any help with this equation would be appreciated.:) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #98757 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=98757\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> reflection is like the image you see in a mirror, the image seems as far away from the other side of the mirror as you are\r<BR>\n" );
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document.write( "the reflected vertices are the same distance from the x-axis (mirror) as the original vertices, but on the other side\r<BR>\n" );
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document.write( "operationally; since the x-axis is the reflector, the x values stay the same and the y values change sign\r<BR>\n" );
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document.write( "new vertices __ A(-6,-3), B(-1,4), C(3,5) </SPAN>\n" );
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