document.write( "Question 134895: A child is 1/3 the age of an older sibling. The sum of the children's ages is 16. How old is the younger child? \n" ); document.write( "
Algebra.Com's Answer #98751 by dbashant(7)![]() ![]() ![]() You can put this solution on YOUR website! First write an equation that describes the relationship between the children's ages. \r \n" ); document.write( "\n" ); document.write( "child's age = 1/3 sibling's age \n" ); document.write( "Let's use C for child's age \n" ); document.write( "and S for sibling's age.\r \n" ); document.write( "\n" ); document.write( "So, we have C = 1/3 S\r \n" ); document.write( "\n" ); document.write( "Next, we know the sum of the ages is 16. So, C + S = 16.\r \n" ); document.write( "\n" ); document.write( "Now that we have 2 equations with 2 unknowns, C and S, we can solve.\r \n" ); document.write( "\n" ); document.write( "If we use substituion, we can put 1/3 S from the first equation in place of C in the second equation.\r \n" ); document.write( "\n" ); document.write( "(1/3 S) + S = 16 Then multiply through by 3 to get rid of the fraction. \n" ); document.write( "S + 3S = 48 Then simplify \n" ); document.write( "4S = 48 Then divide by 4 to solve for S. \n" ); document.write( "S = 12 \n" ); document.write( "Now that we know S = 12, it is easy to solve for C.\r \n" ); document.write( "\n" ); document.write( "Your answer should give the age of the younger child. \n" ); document.write( ":-)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |