document.write( "Question 134865This question is from textbook algebra 2
\n" ); document.write( ": please help me solve this equation x^2 +6x =2 \n" ); document.write( "
Algebra.Com's Answer #98731 by solver91311(24713)\"\" \"About 
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\"x%5E2+%2B6x+=2\"\r
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\n" ); document.write( "\n" ); document.write( "You can either complete the square or use the quadratic formula (which is nothing more than completing the square in general terms).\r
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\n" ); document.write( "\n" ); document.write( "Complete the square solution:\r
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\n" ); document.write( "\n" ); document.write( "The first step is to divide both sides of the equation by the coefficient on the \"x%5E2\" term, but since that coefficient is 1, we can skip this step.\r
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\n" ); document.write( "\n" ); document.write( "The second step is to divide the coefficient on the \"x\" term by 2 and square the result:\r
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\n" ); document.write( "\n" ); document.write( "\"%286%2F2%29%5E2=3%5E2=9\"\r
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\n" ); document.write( "\n" ); document.write( "Step 3: Add the result of step 2 to both sides of the equation\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2+%2B6x+%2B9=2%2B9\"\r
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\n" ); document.write( "\n" ); document.write( "Step 4: You now have a perfect square trinomial on the left, so factor it:\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B3%29%5E2=11\"\r
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\n" ); document.write( "\n" ); document.write( "Step 5: Take the square root of both sides of the equation, remembering to consider both positive and negative roots:\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B3=sqrt%2811%29\" or \"x%2B3=-sqrt%2811%29\"\r
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\n" ); document.write( "\n" ); document.write( "Step 6: Simplify both resulting equations:\r
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\n" ); document.write( "\n" ); document.write( "\"x=-3%2Bsqrt%2811%29\" or \"x=-3-sqrt%2811%29\"\r
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\n" ); document.write( "\n" ); document.write( "And that is all there is.\r
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\n" ); document.write( "\n" ); document.write( "Quadratic Formula Solution:\r
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\n" ); document.write( "\n" ); document.write( "First put your equation into standard form \"ax%5E2%2Bbx%2Bc=0\" by adding -2 to both sides:\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B6x-2=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\" where a is the coefficient on the \"x%5E2\" term, b is the coefficient on the \"x\" term, and c is the constant term, so:\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-6+%2B-+sqrt%28+6%5E2-4%2A1%2A%28-2%29+%29%29%2F%282%2A1%29+\" \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-6+%2B-+sqrt%28+36%2B8+%29%29%2F2+\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-6+%2B-+sqrt%2844%29%29%2F2+\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-6+%2B-+sqrt%284%2A11%29%29%2F2+\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-6+%2B+2sqrt%2811%29%29%2F2+\" or \"x+=+%28-6+-+2sqrt%2811%29%29%2F2+\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+-3+%2B+sqrt%2811%29+\" or \"x+=+-3+-+sqrt%2811%29\"\r
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\n" ); document.write( "\n" ); document.write( "Not surprisingly (I sincerely hope), we got the same answers.
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