document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=134802>Question 134802</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0130443980/algebrahomeworkh>Algebra 1 workbook</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Can you help me solve:\r<BR>\n" );
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document.write( "3b-a=-7<BR>\n" );
document.write( "5a+6b=14 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #98716 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrapro18><B>algebrapro18(249)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrapro18><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=98716\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You would solve this problem using substitution.  The steps for substitution are:<br>\r<BR>\n" );
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document.write( "1) Solve one of the equation for an isolated variable.<BR>\n" );
document.write( "2) Plug in step 1 into the remaining equation and solve for the one variable.<BR>\n" );
document.write( "3) Plug in step 2 into step one and find what the isolated variable is.<BR>\n" );
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document.write( "3b - a = -7<BR>\n" );
document.write( "5a + 6b = 14<br>\r<BR>\n" );
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document.write( "Since 3b - a = -7 has a variable alone we will solve this equation for a.<br>\r<BR>\n" );
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document.write( "3b - a = -7<BR>\n" );
document.write( "-a = -7 - 3b<BR>\n" );
document.write( "a = 7 + 3b<br>\r<BR>\n" );
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document.write( "now plug that into 5a + 6b = 14 and solve for b.<br>\r<BR>\n" );
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document.write( "5a + 6b = 14 --> Plug in a = 7 + 3b into the second equation<BR>\n" );
document.write( "5(7 + 3b) + 3b = 14 --> Distribute the 5 though<BR>\n" );
document.write( "35 + 15b + 3b = 14 --> Combine like terms<BR>\n" );
document.write( "35 + 18b = 14 --> Subtract 35 from both sides<BR>\n" );
document.write( "18b = -21 --> Divide both sides by 18<BR>\n" );
document.write( "b = -7/6<br>\r<BR>\n" );
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document.write( "Now we plug b = -7/6 into a = 7 + 3b and solve for a.<br>\r<BR>\n" );
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document.write( "a = 7 + 3b<BR>\n" );
document.write( "a = 7 + 3(-7/6)<BR>\n" );
document.write( "a = 7 - 7/2<BR>\n" );
document.write( "a = 7/2<br>\r<BR>\n" );
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document.write( "so your solution is a = 7/2 and b = -7/6. </SPAN>\n" );
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