document.write( "Question 134842: Hi,
\n" ); document.write( " Can you help me with this math problem?\r
\n" ); document.write( "\n" ); document.write( "Sovle the inequality.Give answer in interval notation.\r
\n" ); document.write( "\n" ); document.write( "(x + 2)(x - 1)(x - 10) > 0
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Algebra.Com's Answer #98695 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Very clearly, \"x\" cannot be \"10\", \"1\", or \"-2\",
\n" ); document.write( "since those would make the left side = \"0\", and it must be >\"0\"
\n" ); document.write( "\"x+%3E+10\" works because all 3 factors are +
\n" ); document.write( "\"-2+%3C+x+%3C+1\" works also, since the factors are (+)(-)(-) = (+)
\n" ); document.write( "But if \"1+%3C+x+%3C+10\", the factors are (+)(+)(-) = (-)
\n" ); document.write( "If \"x+%3C+-2\", the factors are (-)(-)(-) = (-) also.
\n" ); document.write( "So, the ones that work are:
\n" ); document.write( "\"x+%3E10\" and
\n" ); document.write( "\"-2+%3C+x+%3C+1\" answer
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