document.write( "Question 134840: the question is to find the area of a square with a diagnol length of 15radical 2 \n" ); document.write( "
Algebra.Com's Answer #98679 by solver91311(24713)\"\" \"About 
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The diagonal of a square forms an isoceles right triangle with two of the sides. Using Pythagoras, and remembering that the legs of the triangle are the same length, we have \"c=15sqrt%282%29\", and since \"a=b\", \"a%5E2%2Bb%5E2=a%5E2%2Ba%5E2=2a%5E2\". That means:\r
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\n" ); document.write( "\n" ); document.write( "\"2a%5E2=%2815sqrt%282%29%29%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"2a%5E2=225%282%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"a%5E2=225\"\r
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\n" ); document.write( "\n" ); document.write( "\"a=15\"\r
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\n" ); document.write( "\n" ); document.write( "The area of a square is given by the measure of one of the sides squared, so if the side measures 15, the area is: \"A=15%5E2=225\" square units.\r
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