document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=134831>Question 134831</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Tutor how do I factor 3y^2-14y-24 do I have to find out what y is first?  Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #98668 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=98668\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> factor 3y^2-14y-24 <BR>\n" );
document.write( "Use the AC Method:<BR>\n" );
document.write( "AC = 3*-24 = -72<BR>\n" );
document.write( "B = -14<BR>\n" );
document.write( "---------------<BR>\n" );
document.write( "Think of two numbers whose sum is -72 and whose product is -14<BR>\n" );
document.write( "The numbers are -18 and +4<BR>\n" );
document.write( "------------------------------<BR>\n" );
document.write( "Rewrite the original problem putting -18y+4y in place of -14y:\r<BR>\n" );
document.write( "\n" );
document.write( "= 3y^2-18y+4y-24\r<BR>\n" );
document.write( "\n" );
document.write( "Factor the 1st two and the last two terms separately:\r<BR>\n" );
document.write( "\n" );
document.write( "= 3y(y-6)+4(y-6)\r<BR>\n" );
document.write( "\n" );
document.write( "Factor again:\r<BR>\n" );
document.write( "\n" );
document.write( "= (y-6)(3y+4)\r<BR>\n" );
document.write( "\n" );
document.write( "=====================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );