document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=134781>Question 134781</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0395977223/algebrahomeworkh>Algebra Structure and Method </A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> I have been working on this math problem for awhile now and I was wondering if anyone could help me?  I would deeply appreciate it!!  Please and Thank you!!\r<BR>\n" );
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document.write( "Area Problems<BR>\n" );
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document.write( "A corner lot originally was square lost 185m^2 of area when one of the adjacent streets was widened by 3m and the other was widened by 5m.  Find the new dimensions of the lot. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #98618 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=98618\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A corner lot originally was square lost 185m^2 of area when one of the adjacent streets was widened by 3m and the other was widened by 5m. Find the new dimensions of the lot.<BR>\n" );
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document.write( "Let x = original dimension of the square lot<BR>\n" );
document.write( "Then x^2 = the area of the original lot<BR>\n" );
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document.write( "The new dimensions: (x-3) by (x-5)<BR>\n" );
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document.write( "New lot area = original lot area - 185 sq/m<BR>\n" );
document.write( "(x-3)*(x-5) = x^2 - 185<BR>\n" );
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document.write( "x^2 - 8x + 15 = x^2 - 185<BR>\n" );
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document.write( "x^2 - x^2 - 8x = -185 - 15<BR>\n" );
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document.write( "-8x = -200<BR>\n" );
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document.write( "x = 200/8<BR>\n" );
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document.write( "x = 25 meters the diminsion of the original lot<BR>\n" );
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document.write( "New dimensions:<BR>\n" );
document.write( "25 - 3 = 22 meters<BR>\n" );
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document.write( "25 - 5 = 20 meters<BR>\n" );
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document.write( "Check solution; find the area of both:<BR>\n" );
document.write( "25 * 25 = 625<BR>\n" );
document.write( "22 * 20 = 440<BR>\n" );
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document.write( "differs = 185 \r<BR>\n" );
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