document.write( "Question 134725This question is from textbook College Algebra
\n" ); document.write( ": I am completely lost on how to do these. Any help would be great.
\n" ); document.write( "It says:
\n" ); document.write( "Sketch the graph of the following. Label vertex, x-and y-intercepts.
\n" ); document.write( "f(x)=x^2-x-12\r
\n" ); document.write( "\n" ); document.write( "Vertex=( , )
\n" ); document.write( "x-intercepts=( , );( , )
\n" ); document.write( "y-intercept=( , ) \n" ); document.write( "

Algebra.Com's Answer #98605 by cbcrawford978(7) $\"\"$ $\"About$

You can put this solution on YOUR website!
The easiest way to solve this is on a graph. But i'm going to factor the equation to find ONLY the x-intercepts..... $\"x%5E2-x-12\"$ This factors into $\"x-4=0\"$ and $\"x%2B3=0\"$ if you use the FOIL method $\"%28x-4%29%28x-3%29\"$ you should get $\"x%5E2-x-12\"$ . The reason you set $\"x-4\"$ and $\"x%2B3\"$ to \"0\" is so you can solve for \"x.\" x-4=0.....x=4 and x+3=0......x=-3. The x-intercepts are (4,0) and (-3,0). You should make a graph to find the y-intercept. Since the highest power in the equation is \"2\" there should only be one y-intercept. The vertex is the lowest point on the graph. $\"graph%28300%2C200%2C-5%2C5%2C-15%2C15%2Cx%5E2-x-12%29\"$ \n" ); document.write( "

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