document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=20508>Question 20508</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle playing field is 5ft. less than twice its width. If the perimeter of the playing field is 230 ft, find the length and width of the field. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #9858 by </B><A HREF=/tutors/aboutme.mpl?userid=suresh><B>suresh(20)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=suresh><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=9858\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter of the rectangle is = 2 ( l + b ) ,where l is the length and b is the breath of the rectangle.\r<BR>\n" );
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document.write( "Let b be the width of the rectangle.\r<BR>\n" );
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document.write( "Given, l = 2 b - 5.\r<BR>\n" );
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document.write( "Also perimeter = 230 ft.\r<BR>\n" );
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document.write( "Therefore, 2 (2b - 5 + b ) = 230\r<BR>\n" );
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document.write( "2 ( 3b - 5) = 230\r<BR>\n" );
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document.write( "6b-10=230\r<BR>\n" );
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document.write( "6b=240<BR>\n" );
document.write( "b=40.\r<BR>\n" );
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document.write( "l=2(40)-5=80-5=75.\r<BR>\n" );
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document.write( "Hence, l = 75  and b= 40\r<BR>\n" );
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