document.write( "Question 134750: A city wants to buy some animals but they only have 100 dollars. Horses cost 10 dollars cows cost 3 dollars and ducks cost 50 cents. How many animals can they buy. \r
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\n" ); document.write( "\n" ); document.write( "10x+3y+.5z+100 I simplified for x and came up with x=10+-.3y+.05z now do I simplify for Y and then put both statements into the equaltion? \r
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Algebra.Com's Answer #98577 by stanbon(75887)\"\" \"About 
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A city wants to buy some animals but they only have 100 dollars. Horses cost 10 dollars cows cost 3 dollars and ducks cost 50 cents. How many animals can they buy. \r
\n" ); document.write( "\n" ); document.write( "10x+3y+.5z <= 100 \r
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\n" ); document.write( "Make a list of numbers of horses, cows, ducks
\n" ); document.write( "There are no more than 10 horses so put the numbers 0 through 10
\n" ); document.write( "below horses.
\n" ); document.write( "with zero horses list the possible numbers of cows from 0 to 33
\n" ); document.write( "with zero horses and zero cows you can buy 0 to 200 ducks
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\n" ); document.write( "With one horse the possible # of cows and ducks change.
\n" ); document.write( "Similarly with two horses, or three etc.
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\n" ); document.write( "Comment: there are a lot of possible combinations.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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