document.write( "Question 20507: Science and medicine. Martina leaces home at 9 A.M., bicycling at a rate of 24mi/h. Two hours later, John leaves, driving at the rate of 48 mi/h. At what time will John catch up with Martina? \n" ); document.write( "

Algebra.Com's Answer #9857 by wuwei96815(245) $\"\"$ $\"About$

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This problem involves the equation distance = speed x time, or at least part of the equation.\r
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\n" ); document.write( "\n" ); document.write( "The question is really asking at what point will the distance that Martina travels be equal to the distance that John travels?\r
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\n" ); document.write( "\n" ); document.write( "Martina's distance = 24 mph x (t + 2) because she starts off two hours before John.\r
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\n" ); document.write( "\n" ); document.write( "John's distance = 48mph x t\r
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\n" ); document.write( "\n" ); document.write( "24mph x (t+2) = 48mph x t
\n" ); document.write( "24t + 48 = 48t
\n" ); document.write( "48 = 48t-24t
\n" ); document.write( "48 = 24t
\n" ); document.write( "2 = t\r
\n" ); document.write( "\n" ); document.write( "They will meet 2 hours after John starts. That will be at 1 P.M.\r
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\n" ); document.write( "\n" ); document.write( "Did you understand the solution? \n" ); document.write( "

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