document.write( "Question 134734: log(x-2)+log(2x-3)=2Logx \n" ); document.write( "

Algebra.Com's Answer #98565 by vleith(2983) $\"\"$ $\"About$

You can put this solution on YOUR website!
Given: $\"log%28x-2%29%2Blog%282x-3%29=2Logx\"$
\n" ); document.write( " $\"10%5E%28log%28x-2%29%2Blog%282x-3%29%29=10%5E%282Logx%29+\"$
\n" ); document.write( " $\"10%5E%28log%28x-2%29%29%2A10%5E%28log%282x-3%29%29=10%5E%282Logx%29+\"$
\n" ); document.write( " $\"%28x-2%29%282x-3%29+=+x%5E2+\"$
\n" ); document.write( " $\"2x%5E2+-7x+%2B+6+=+x%5E2\"$
\n" ); document.write( " $\"x%5E2+-7x+%2B+6+=+0\"$
\n" ); document.write( " $\"%28x+-1%29%28x-6%29+=+0+\"$
\n" ); document.write( "x = 1, 6 are possible solutions\r
\n" ); document.write( "\n" ); document.write( "Verify
\n" ); document.write( "Does Log(4) + Log(9) = 2*Log(6) ??
\n" ); document.write( "Does Log(-1) + Log(-1) = 2*Log(1) --> there is no such thing as a real number with a negative log, so 1 is not an answer. \n" ); document.write( "

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