document.write( "Question 134723: I do not know where to begin:
\n" ); document.write( "a^2+2a-24/a+1
\n" ); document.write( "divided by
\n" ); document.write( "a^2-a-12/(a+1)^2
\n" ); document.write( "I think I should divided the top and bottom by a-1 but I am not really sure
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Algebra.Com's Answer #98556 by vleith(2983)\"\" \"About 
You can put this solution on YOUR website!
Given: \"%28%28a%5E2%2B2a-24%29%2F%28a%2B1%29%29+%2F+%28%28a%5E2-a-12%29%2F%28a%2B1%29%5E2%29+\"\r
\n" ); document.write( "\n" ); document.write( "Multiply both top and bottom by (a+1) \"%28a%2B1%29%2F%28a%2B1%29\"
\n" ); document.write( "Given: \"%28%28a%5E2%2B2a-24%29%2F1%29+%2F+%28%28a%5E2-a-12%29%2F%28a%2B1%29%29+\"\r
\n" ); document.write( "\n" ); document.write( "Factor
\n" ); document.write( "\"+%28%28%28a%2B6%29%28a-4%29%29%2F1%29+%2F+%28%28%28a-4%29%28a-3%29%29%2F%28a%2B1%29%29+\"\r
\n" ); document.write( "\n" ); document.write( "The term \"%28a-4%29\"{ occurs on both the numerator and the denominator, so it cancels to 1
\n" ); document.write( "\"+%28%28%28a%2B6%29%29%2F1%29+%2F+%28%28%28a-3%29%29%2F%28a%2B1%29%29+\"\r
\n" ); document.write( "\n" ); document.write( "Now, as we did in the earlier problem, take the inverse of the denominator and multiply that times the numerator
\n" ); document.write( "\"+%28%28%28a%2B6%29%29%2F1%29+%2A+%28%28%28a%2B1%29%29%2F%28a-3%29%29+\"
\n" ); document.write( "Simplify
\n" ); document.write( "\"+%28%28a%2B6%29%28a%2B1%29%29%2F%28a-3%29+\"
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