document.write( "Question 134722This question is from textbook
\n" ); document.write( ": Simplify the complex fraction
\n" ); document.write( "1-5/a-1
\n" ); document.write( "divided by
\n" ); document.write( "3-2/a-1
\n" ); document.write( "I did not know if I was supposed to multiply each by 1 and work from there or what step should I take. I would appreciate any help possible
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Algebra.Com's Answer #98554 by vleith(2983)\"\" \"About 
You can put this solution on YOUR website!
You need to use more parens. It is hard to know what your question really is without them.\r
\n" ); document.write( "\n" ); document.write( "I'll assume you meant \"%281-%285%2F%28a-1%29%29%29+%2F+%283+-+%282%2F%28a-1%29%29%29\"\r
\n" ); document.write( "\n" ); document.write( "you need to find a common denominator for both the numberator terms and the denominator terms.\r
\n" ); document.write( "\n" ); document.write( "\"%28%281%28a-1%29-5%29%2F%28a-1%29%29+%2F+%28%283%28a-1%29+-+2%29%2F%28a-1%29%29\"\r
\n" ); document.write( "\n" ); document.write( "Turns out that both fractions have the same denominator \"%28a-1%29\"\r
\n" ); document.write( "\n" ); document.write( "Dividing two fractions is the same as multipling the numerator fraction by the inverse of the denominator fraction.\r
\n" ); document.write( "\n" ); document.write( "\"%28%281%28a-1%29-5%29%2F%28a-1%29%29+%2A+%28%28a-1%29%2F%283%28a-1%29+-+2%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "Now \"%28a-1%29%2F%28a-1%29\" = 1 so those terms \"cancel\", leaving\r
\n" ); document.write( "\n" ); document.write( "\"%28%281%28a-1%29-5%29%2F%283%28a-1%29+-+2%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"%28a+-+1+-+5%29%2F+%283a+-3+-2%29\"
\n" ); document.write( "\"+%28a-6%29+%2F+%283a-5%29+\"
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