document.write( "Question 134721: The Fundamental Theorem of Algebra
\n" ); document.write( "Use the given zero to find the remaining zeros of each polynomial function.\r
\n" ); document.write( "\n" ); document.write( "P(x)=x^4-6x^3+71x^2-146x+530; 2+7i
\n" ); document.write( "x intercepts = 2+7i & 2-7i
\n" ); document.write( "x=2-7i
\n" ); document.write( "=x-2+7i=0=(x-(2-7i))=0
\n" ); document.write( "(x-(2-7i))(x-(2+7i))=
\n" ); document.write( "x^2-x(2+7i)-x(2-7i)+(2+7i)(2-7i)=
\n" ); document.write( "x^2-2x-7xi-2x+7xi+53=
\n" ); document.write( "x^2-4x+53=
\n" ); document.write( "x^4-6x^3+71x^2-146x+530/x^2-4x+53=
\n" ); document.write( "x^2-2x+10=
\n" ); document.write( "(x^2-4x+53)(x^2-2x+10)
\n" ); document.write( "Now I'm stuck. Could really use some help
\n" ); document.write( "Thanks so much
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Algebra.Com's Answer #98551 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
You have the correct steps. \r
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\n" ); document.write( "\n" ); document.write( "All that you need to do is solve for x in \"x%5E2-2x%2B10\"\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for x:\r
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\n" ); document.write( "\n" ); document.write( "Starting with the general quadratic\r
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\n" ); document.write( "\n" ); document.write( "\"ax%5E2%2Bbx%2Bc=0\"\r
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\n" ); document.write( "\n" ); document.write( "the general solution using the quadratic equation is:\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"\r
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\n" ); document.write( "\n" ); document.write( "So lets solve \"x%5E2-2%2Ax%2B10=0\" ( notice \"a=1\", \"b=-2\", and \"c=10\")\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28--2+%2B-+sqrt%28+%28-2%29%5E2-4%2A1%2A10+%29%29%2F%282%2A1%29\" Plug in a=1, b=-2, and c=10\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%282+%2B-+sqrt%28+%28-2%29%5E2-4%2A1%2A10+%29%29%2F%282%2A1%29\" Negate -2 to get 2\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%282+%2B-+sqrt%28+4-4%2A1%2A10+%29%29%2F%282%2A1%29\" Square -2 to get 4 (note: remember when you square -2, you must square the negative as well. This is because \"%28-2%29%5E2=-2%2A-2=4\".)\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%282+%2B-+sqrt%28+4%2B-40+%29%29%2F%282%2A1%29\" Multiply \"-4%2A10%2A1\" to get \"-40\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%282+%2B-+sqrt%28+-36+%29%29%2F%282%2A1%29\" Combine like terms in the radicand (everything under the square root)\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%282+%2B-+6%2Ai%29%2F%282%2A1%29\" Simplify the square root (note: If you need help with simplifying the square root, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%282+%2B-+6%2Ai%29%2F%282%29\" Multiply 2 and 1 to get 2\r
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\n" ); document.write( "\n" ); document.write( "After simplifying, the quadratic has roots of\r
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\n" ); document.write( "\n" ); document.write( "\"x=1+%2B+3%2Ai\" or \"x=1+-+3%2Ai\"\r
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\n" ); document.write( "\n" ); document.write( "So the remaining zeros are \r
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\n" ); document.write( "\n" ); document.write( "\"x=1+%2B+3%2Ai\" or \"x=1+-+3%2Ai\"
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