document.write( "Question 134617: find the dimensions of the rectangle. if its length is twice its width. perimeter is equal to 208. \n" ); document.write( "
Algebra.Com's Answer #98544 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! L=2W \n" ); document.write( "2*W+(2*2W)=208 \n" ); document.write( "2W+4W=208 \n" ); document.write( "6W=208 \n" ); document.write( "W=208/6 \n" ); document.write( "W=34.66667 ANSWER FOR THE WIDTH. \n" ); document.write( "L=2*34.66667 \n" ); document.write( "L=69.33333 ANSWER. \n" ); document.write( "PROOF: \n" ); document.write( "2*34.6667+2*2*34.6667=208 \n" ); document.write( "69.3333+138.66667=208 \n" ); document.write( "208=208 \n" ); document.write( " |