document.write( "Question 134716: I am having so much trouble with this question. I will show you the original question and then will show what I have. Please complete the problem for me from start to finish so that I am no longer as confused as I am now. This is what I have:\r
\n" ); document.write( "\n" ); document.write( "(3x)^-1/3=\r
\n" ); document.write( "\n" ); document.write( "3^-1/3 * x^-1/3=\r
\n" ); document.write( "\n" ); document.write( "1/3^1/3 * 1/x^-1/3=\r
\n" ); document.write( "\n" ); document.write( "3^1/3= 3cubert3=\r
\n" ); document.write( "\n" ); document.write( "1/3cubert3x\r
\n" ); document.write( "\n" ); document.write( "I am not allowed to leave radicals in the denominator, I am completely confused, can you please solve the original? The original problem again is (3x)^-1/3\r
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Algebra.Com's Answer #98534 by stanbon(75887) $\"\"$ $\"About$

You can put this solution on YOUR website!
(3x)^(-1/3)\r
\n" ); document.write( "\n" ); document.write( "= 1/(3x)^(1/3)\r
\n" ); document.write( "\n" ); document.write( "Multiply numerator and denominator by (3x)^(2/3) to get:\r
\n" ); document.write( "\n" ); document.write( "= [(3x)^(2/3)]/3x
\n" ); document.write( "
\n" ); document.write( "======================
\n" ); document.write( "Cheers,
\n" ); document.write( "stan H.
\n" ); document.write( " \n" ); document.write( "

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