document.write( "Question 134679: Two planes leave Pittsburgh and Philadelphia at the same time, each going to the other city. One plane flies 30 miles per hour faster than the other. Find the ground speed of each plane if the cities are 260 miles apart and the planes pass one another after 40 minutes of flying time. \n" ); document.write( "
Algebra.Com's Answer #98520 by rajagopalan(174)\"\" \"About 
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LET THE SPED OF PLANE 1 = X
\n" ); document.write( "LET THE SPED OF PLANE 2 = X+30
\n" ); document.write( "DISTANCE IN 40 MINUTES OF FLYING FOR PLANE 1=X(40/60)=(2/3)X
\n" ); document.write( "DISTANCE IN 40 MINUTES OF FLYING FOR PLANE 2=(X+30)(40/60)=(2/3)(X+30)
\n" ); document.write( "ADD THE TWO DISTANCES,
\n" ); document.write( "(2/3)X + (2/3)(X+30)=260
\n" ); document.write( "2X/3+2X/3+20=260
\n" ); document.write( "4X/3=260-20
\n" ); document.write( "4X/3=240
\n" ); document.write( "X=240*3/4
\n" ); document.write( "X=180
\n" ); document.write( "THE SPED OF PLANE 1 = X =180
\n" ); document.write( "THE SPED OF PLANE 2 = X+30=180+30=210
\n" ); document.write( "SPEED UNIT MILES PER HOUR
\n" ); document.write( "OKAY\r
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