document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=134641>Question 134641</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write as a single power:<BR>\n" );
document.write( "[27^(-x+2)*(1/9)^2x]/3(81)^(x-4)<BR>\n" );
document.write( "My answer is 3^(-11x+22). Can someone Please confirm this for me?? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #98500 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=98500\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> [27^(-x+2)*(1/9)^2x]/3(81)^(x-4)<BR>\n" );
document.write( "My answer is 3^(-11x+22). Can someone Please confirm this for me??<BR>\n" );
document.write( "-----------------<BR>\n" );
document.write( "= [3^(-3x+6)*3^(-4x)]/[3^(5x-20)]\r<BR>\n" );
document.write( "\n" );
document.write( "= [3^(-7x+6)]/[3^(5x-20)]\r<BR>\n" );
document.write( "\n" );
document.write( "= 3^(-12x+26)<BR>\n" );
document.write( "=============================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );