document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=20400>Question 20400</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write down the equation for the line that passes through the point (3, -2) and is perpendicular to the line y = 2x + 4.\r<BR>\n" );
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document.write( "How do I do this?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #9850 by </B><A HREF=/tutors/aboutme.mpl?userid=suresh><B>suresh(20)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=suresh><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=9850\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To find the equation of line passing through (3,-2)<BR>\n" );
document.write( "and perpendicular to y=2x+4\r<BR>\n" );
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document.write( "We know that the perpendicular line for ax+by+c = 0 is -bx+ay+k=0\r<BR>\n" );
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document.write( "So the perpendicular line to 2x-y+4=0 is x+2y+k =0 ----->(1)\r<BR>\n" );
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document.write( "We have to find the value of k.\r<BR>\n" );
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document.write( "Since the line passing through the point(3,-2),it satisfies the equation.\r<BR>\n" );
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document.write( "plug x=3 and y = -2 in (1)\r<BR>\n" );
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document.write( "3+2(-2)+k =0.\r<BR>\n" );
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document.write( "-1 + k = 0.\r<BR>\n" );
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document.write( "k=1.\r<BR>\n" );
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document.write( "Plug the value of k in (1) we get the required line.\r<BR>\n" );
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document.write( "Therefore the required line is, x+2y+1=0. </SPAN>\n" );
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