document.write( "Question 134624: Solve using the addition principle.\r
\n" ); document.write( "\n" ); document.write( "2x+8> x +10
\n" ); document.write( "The solution set is X X > __
\n" ); document.write( "Help me please again I do not understand what I am supposed to do with this.
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Algebra.Com's Answer #98493 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
\"2x%2B8%3E+x+%2B10\"\r
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\n" ); document.write( "\n" ); document.write( "You can add -x to both sides:\r
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\n" ); document.write( "\n" ); document.write( "\"2x-x%2B8%3Ex-x%2B10\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B8%3E10\"\r
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\n" ); document.write( "\n" ); document.write( "Then add -8 to both sides:\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B8-8%3E10-8\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%3E2\"\r
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\n" ); document.write( "\n" ); document.write( "Since we never multiplied or divided by a negative number, the sense of the inequality remains the same throughout.\r
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\n" ); document.write( "\n" ); document.write( "The solution set is {x|x > 2}\r
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\n" ); document.write( "\n" ); document.write( "Sanity check:\r
\n" ); document.write( "\n" ); document.write( "Pick a number larger than 2 and substitute:
\n" ); document.write( "3 is larger than 2:\r
\n" ); document.write( "\n" ); document.write( "\"2%283%29%2B8%3E%283%29%2B10\"
\n" ); document.write( "\"14%3E13\", true statement -- so far so good.\r
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\n" ); document.write( "\n" ); document.write( "Pick a number smaller than 2
\n" ); document.write( "1 is smaller than 2:\r
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\n" ); document.write( "\n" ); document.write( "\"2%281%29%2B8%3E1%2B10\"
\n" ); document.write( "\"10%3E11\", false statement, as expected.\r
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\n" ); document.write( "\n" ); document.write( "The above does NOT conclusively prove the answer, but it does give you a nice warm fuzzy feeling that you are most likely correct.
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