document.write( "Question 134624: Solve using the addition principle.\r
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document.write( "2x+8> x +10
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document.write( "The solution set is X X > __
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document.write( "Help me please again I do not understand what I am supposed to do with this. \n" );
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Algebra.Com's Answer #98493 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You can add -x to both sides:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then add -8 to both sides:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since we never multiplied or divided by a negative number, the sense of the inequality remains the same throughout.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The solution set is {x|x > 2}\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Sanity check:\r \n" ); document.write( "\n" ); document.write( "Pick a number larger than 2 and substitute: \n" ); document.write( "3 is larger than 2:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Pick a number smaller than 2 \n" ); document.write( "1 is smaller than 2:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The above does NOT conclusively prove the answer, but it does give you a nice warm fuzzy feeling that you are most likely correct. \n" ); document.write( " |