document.write( "Question 134616: one number is 4 less than 3 times a second number. if 3 more than twice the first number is decreased by twice the second, the result is 11. find both numbers. \n" ); document.write( "

Algebra.Com's Answer #98484 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Call the 1st number $\"a\"$
\n" ); document.write( "Call the 2nd number $\"b\"$
\n" ); document.write( " $\"a+=+3b+-+4\"$
\n" ); document.write( " $\"2a+%2B+3+-+2b+=+11\"$
\n" ); document.write( "Substitute $\"a\"$ in the 1st for $\"a\"$ in the 2nd
\n" ); document.write( " $\"2%2A%283b+-+4%29+%2B+3+-+2b+=+11\"$
\n" ); document.write( " $\"6b+-+8+%2B+3+-+2b+=+11\"$
\n" ); document.write( " $\"4b+=+11+%2B+8+-+3\"$
\n" ); document.write( " $\"4b+=+16\"$
\n" ); document.write( " $\"b+=+4\"$
\n" ); document.write( " $\"a+=+3b+-+4\"$
\n" ); document.write( " $\"a+=+3%2A4+-+4\"$
\n" ); document.write( " $\"a+=+8\"$
\n" ); document.write( "The numbers are 8 and 4
\n" ); document.write( "check:
\n" ); document.write( " $\"2a+%2B+3+-+2b+=+11\"$
\n" ); document.write( " $\"2%2A8+%2B+3+-+2%2A4+=+11\"$
\n" ); document.write( " $\"19+-+8+=+11\"$
\n" ); document.write( " $\"11+=+11\"$
\n" ); document.write( " $\"a+=+3b+-+4\"$
\n" ); document.write( " $\"8+=+3%2A4+-+4\"$
\n" ); document.write( " $\"8+=+8\"$
\n" ); document.write( "OK \n" ); document.write( "

\n" );