document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=20480>Question 20480</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Here is another one,<BR>\n" );
document.write( "solve each system by the addition method.\r<BR>\n" );
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document.write( "2x=2-y<BR>\n" );
document.write( "3x+y=-1\r<BR>\n" );
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document.write( " Help,I have no clue.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #9848 by </B><A HREF=/tutors/aboutme.mpl?userid=suresh><B>suresh(20)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=suresh><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=9848\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The given equations are,<BR>\n" );
document.write( "2x = 2 - y------------>(1)\r<BR>\n" );
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document.write( "3x + y = -1----------->(2)\r<BR>\n" );
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document.write( "Eqn (1) becomes, -2x - y = -2 ------->(3)\r<BR>\n" );
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document.write( "Adding (1) and (3),\r<BR>\n" );
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document.write( "x = - 3.\r<BR>\n" );
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document.write( "Plug x = -3 in (1), we have  2 ( -3 ) = 2 - y\r<BR>\n" );
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document.write( "-6 = 2 - y<BR>\n" );
document.write( "-y =  - 8.\r<BR>\n" );
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document.write( "y = 8\r<BR>\n" );
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document.write( "Hence x = -3 and y = 8<BR>\n" );
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