document.write( "Question 134588: Dear Tutor\r
\n" ); document.write( "\n" ); document.write( "Could you please help me with this investigation question from an old Maths Textbook?
\n" ); document.write( "Please solve this inequation:\r
\n" ); document.write( "\n" ); document.write( "\"+3%5Ex+%3E+x%5E3+\"\r
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\n" ); document.write( "\n" ); document.write( "The book only gives the answer: \"+x%21=3+\". I tried to use \"log\" or \"cube roots\" to find out x but it seemed neither of them helped. Therefore, could you please show me how do you get \"+x%21=3+\"? Thank you in advance. :-)
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Algebra.Com's Answer #98453 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
3^x > x^3
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\n" ); document.write( "Graph the left side and the right side separately on the same set of axes:
\n" ); document.write( "\"graph%28400%2C300%2C-10%2C10%2C-10%2C15%2C3%5Ex%2Cx%5E3%29\"
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\n" ); document.write( "Observe where 3^x is above x^3:
\n" ); document.write( "Ans: x< 2.4780527...
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\n" ); document.write( "I graphed them on a TI calculator so I could better analyze the problem.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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