document.write( "Question 134562This question is from textbook Algebra Structure and Method
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document.write( ": I have been working on this math problem and I got an answer, but I am not sure if I did it right!! I was wondering if anyone could help me? I would deeply appreciate it!! Please and Thank You!\r
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document.write( "This is the work that I did
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document.write( "It takes a plane 40min to fly from Boston to Los Angeles at 525mi/h than it does to return at 600mi/h. How far apart are the cities?
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document.write( "My Chart
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document.write( " r * t =d
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document.write( "trip 525 * t+.6 = 525(t+.6) 40/60=.6
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document.write( "return 600 * t = 600t
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document.write( "t=time in hours
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document.write( "600t=525(t+.6)
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document.write( "600t=525t + 315
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document.write( "-525t -525t
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document.write( "75t=315
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document.write( "divide by 75t and t=4.2\r
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document.write( "I don't know if this answer is right, but I hope someone could help me. \n" );
document.write( "
Algebra.Com's Answer #98451 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! It takes a plane 40min to fly from Boston to Los Angeles at 525mi/h than it does to return at 600mi/h. How far apart are the cities? \n" ); document.write( "My Chart \n" ); document.write( "r * t =d \n" ); document.write( "trip 525 * (t+(2/3)) = 525t + 525(2/3) \n" ); document.write( "return 600 * t = 600t \n" ); document.write( "t=time in hours \n" ); document.write( "600t=525(t+(2/3)) \n" ); document.write( "600t=525t + 525*(2/3) \n" ); document.write( "-525t -525t \n" ); document.write( "75t=525(2/3) \n" ); document.write( "divide by 75 to get and t= 4 2/3 = 14/3 \n" ); document.write( "------------------------ \n" ); document.write( "distance from Boston to LA = (14/3)*600 = 14*200 = 2800 miles \n" ); document.write( "===================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |