document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=134561>Question 134561</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0395977223/algebrahomeworkh>Algebra Structure and Method </A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> I have been struggling on this math problem for a while now and I was wondering if anyone could help me?  I would deeply appreciate it!  Please and Thank You!\r<BR>\n" );
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document.write( "Rate-Time-Distance Problems<BR>\n" );
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document.write( "At 7:00am Joe starts jogging at 6mi/h.  At 7:10am Ken starts off after him.  How fast must Ken run in order to overtake him at 7:30am? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #98444 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=98444\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Ken's running speed: x<BR>\n" );
document.write( "Joe's running speed: 6 mph\r<BR>\n" );
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document.write( "Since we want to know about how fast Ken is running when he catches Joe, the distance they travel must be the same.\r<BR>\n" );
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document.write( "We also know that Joe is running for 30 minutes or one-half hour, and Ken is running for 20 minutes or one-third of an hour.\r<BR>\n" );
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document.write( "Joe's trip:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=d=6%2A%281%2F2%29=3 ALIGN=MIDDLE  ALT=\"d=6%2A%281%2F2%29=3\"   DISABLED_style= \"max-width:90%; height:auto;\" > miles\r<BR>\n" );
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document.write( "Ken's trip:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=d=x%2A%281%2F3%29 ALIGN=MIDDLE  ALT=\"d=x%2A%281%2F3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > and that must also equal 3 miles.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2A1%2F3=3 ALIGN=MIDDLE  ALT=\"x%2A1%2F3=3\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=9 ALIGN=MIDDLE  ALT=\"x=9\"   DISABLED_style= \"max-width:90%; height:auto;\" > miles per hour.\r<BR>\n" );
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document.write( "Check:<BR>\n" );
document.write( "Joe: 6 mph for 1/2 hour = 3 miles<BR>\n" );
document.write( "Ken: 9 mph for 1/3 hour = 3 miles<BR>\n" );
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