document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=134552>Question 134552</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "How many ways can a committee of 4 be chosen from 5 women and 6 men if the committee much have at least one woman? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #98435 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=98435\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> THE FIRST ONE CHOSEN IS A WOMAN OR 6 CHANCES.<BR>\n" );
document.write( "THE SECOND THROUGH THE FOURTH COMMITTEE MEMBER IS 5*4*3=60<BR>\n" );
document.write( "6*60=360 TOTAL CHOICES FOR A 4 MEMBER COMMITTEE OF 1 WOMAN & 3 MEN. </SPAN>\n" );
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