document.write( "Question 134466:
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document.write( "An airplane, flying against the wind dierction, travels 3000 miles between 2 cities in 6 hrs and 15 mts. In the return flight it travels the same distance but in 5 hrs. \r
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document.write( "Find the velocity of the plane in still air and the wind velocity, assuming that both remained constant in the round trip. \n" );
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Algebra.Com's Answer #98434 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! 3000/6.25=480 PLANE SPEED AGAINST THE WIND \n" ); document.write( "3000/5=600 PLANE SPEED WITH THE WIND \n" ); document.write( "(600-480)/2=120/2=60 MPH FOR THE WIND \n" ); document.write( "PROOF: \n" ); document.write( "600-60=480+60 \n" ); document.write( "540=540 SPEED FO THE PLANE IN STILL AIR.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |