document.write( "Question 134535: John mixes a certain amount of 10% isopropyl mixture with 60 gallons of a 20% isopropyl solution, and the resulting mixture is 16% isopropyl. How much of the 10% isopropyl did he add? \n" ); document.write( "

Algebra.Com's Answer #98418 by josmiceli(19441) $\"\"$ $\"About$

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In words:
\n" ); document.write( "(gallons of isopropyl) / (gallons of mixture) = 16%
\n" ); document.write( "Let $\"x\"$ = amount of 10% mixture to be added
\n" ); document.write( " $\"60\"$ gallons = amount of 20% mixture added
\n" ); document.write( "The total gallons of mixture = $\"x+%2B+60\"$
\n" ); document.write( " $\"%28.1x+%2B+.2%2A60%29+%2F+%28x+%2B+60%29+=+.16\"$
\n" ); document.write( " $\"%28.1x+%2B+12%29+%2F+%28x+%2B+60%29+=+.16\"$
\n" ); document.write( "multiply each sides by $\"x+%2B+60\"$
\n" ); document.write( " $\".1x+%2B+12+=+.16%28x+%2B+60%29\"$
\n" ); document.write( " $\".1x+%2B+12+=+.16x+%2B+9.6\"$
\n" ); document.write( " $\".06x+=+2.4\"$
\n" ); document.write( " $\"x+=+40\"$
\n" ); document.write( "He added 40 gallons of the isopropyl mixture
\n" ); document.write( "check:
\n" ); document.write( " $\"%28.1x+%2B+.2%2A60%29+%2F+%28x+%2B+60%29+=+.16\"$
\n" ); document.write( " $\"%28.1%2A40+%2B+.2%2A60%29+%2F+%2840+%2B+60%29+=+.16\"$
\n" ); document.write( " $\"%284+%2B+12%29+%2F+100+=+.16\"$
\n" ); document.write( " $\"16%2F100+=+.16\"$
\n" ); document.write( " $\".16+=+.16\"$
\n" ); document.write( "OK \n" ); document.write( "

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