document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=134495>Question 134495</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I hope u can help me with this .<BR>\n" );
document.write( "two angles are supplementary. one angle is 9degrees more than twice the other angle. Find angles.\r<BR>\n" );
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document.write( "thank u.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #98413 by </B><A HREF=/tutors/aboutme.mpl?userid=dbashant><B>dbashant(7)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dbashant><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=98413\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Angle x and angle y are supplementary, so x + y = 180.<BR>\n" );
document.write( "angle x is 9 more than twice angle y, so x = 2y + 9.<BR>\n" );
document.write( "substituing 2y + 9 for x in the first equation, we get (2y + 9) + y = 180.\r<BR>\n" );
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document.write( "Solve for y - 2y + 9 + y = 180    add the y's together<BR>\n" );
document.write( "              3y + 9 = 180        subtract 9 from each side   <BR>\n" );
document.write( "              3y = 171            divide both sides by 3  <BR>\n" );
document.write( "               y = 57<BR>\n" );
document.write( "So, if x + y = 180 then x + 57 = 180 and x = 123<BR>\n" );
document.write( "So x = 123.  And y = 57.\r<BR>\n" );
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document.write( "To check - Is 123  9 more than twice 57?  (2 X 57) + 9 = 114 + 9 = 123  CHECK!<BR>\n" );
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