document.write( "Question 134506: The height in feet above the ground of a ball thrown straight up with an initial velocity of 96 ft/sec is given by the formula h(t)=-16t^2 + 96t + 4.
\n" ); document.write( "where T is the time, in seconds, after the ball is thrown. find the values of T for which the height of the ball is 48 feet. find the exact solutions. \n" ); document.write( "
Algebra.Com's Answer #98390 by rajagopalan(174)\"\" \"About 
You can put this solution on YOUR website!
h(t)=-16t^2 + 96t + 4.
\n" ); document.write( "48=-16t^2+96t+4
\n" ); document.write( "-16t^2+96t+4=48
\n" ); document.write( "-16t^2+96t+4-48=0
\n" ); document.write( "-16t^2+96t-44=0
\n" ); document.write( "divide thro by 4
\n" ); document.write( "-4t^2+24t-11=0
\n" ); document.write( "split mid tem into 22t+2t
\n" ); document.write( "-4t^2+24t-11=0
\n" ); document.write( "-4t^2+22t+2t-11=0
\n" ); document.write( "-2t(2t-11)+1(2t-11)=0
\n" ); document.write( "(-2t+1)(2t-11)=0
\n" ); document.write( "giving (-2t+1)=0 and t=0.5
\n" ); document.write( "2t-11=0 giving t=5.5
\n" ); document.write( "Ans 0.5 and 5.5 seconds from start of throw respectively for onward and return paths.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );