document.write( "Question 134501: The perimeter of a rectangle is 72 inches. If the width and length are each increased by 6 inches, their ratio will be 7:9. What are the dimensions of the original rectangle? \n" ); document.write( "
Algebra.Com's Answer #98388 by rajagopalan(174)![]() ![]() You can put this solution on YOUR website! Let L=Lenth, B=Width \n" ); document.write( "given: \n" ); document.write( "Perimeter=2L+2B=72 \n" ); document.write( "L+B=36....EQN 1 \n" ); document.write( "Also B+6:L+6=7:9 \n" ); document.write( "in a ratio product of mid terms = product of extreme terms \n" ); document.write( "7(L+6)=9(B+6) \n" ); document.write( "7L+42=9B+54 \n" ); document.write( "7L-9B=54-42=12 \n" ); document.write( ".. \n" ); document.write( "7L-9B=12 \n" ); document.write( "9L+9B=324 FROM EQN 1 (MUTIPLIED BY 9) \n" ); document.write( "Adding 16L=336 \n" ); document.write( "L=336/16=21 \n" ); document.write( "B=36-21=15\r \n" ); document.write( "\n" ); document.write( "So answer : Length = 21 and width=15 \n" ); document.write( "Verification\r \n" ); document.write( "\n" ); document.write( "add 6 to both \n" ); document.write( "L:B=21+6:15+6 \n" ); document.write( "L:B=27:21 \n" ); document.write( "L:B=9:7 \n" ); document.write( "Okay \n" ); document.write( " \n" ); document.write( " |