document.write( "Question 134501: The perimeter of a rectangle is 72 inches. If the width and length are each increased by 6 inches, their ratio will be 7:9. What are the dimensions of the original rectangle? \n" ); document.write( "
Algebra.Com's Answer #98388 by rajagopalan(174)\"\" \"About 
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Let L=Lenth, B=Width
\n" ); document.write( "given:
\n" ); document.write( "Perimeter=2L+2B=72
\n" ); document.write( "L+B=36....EQN 1
\n" ); document.write( "Also B+6:L+6=7:9
\n" ); document.write( "in a ratio product of mid terms = product of extreme terms
\n" ); document.write( "7(L+6)=9(B+6)
\n" ); document.write( "7L+42=9B+54
\n" ); document.write( "7L-9B=54-42=12
\n" ); document.write( "..
\n" ); document.write( "7L-9B=12
\n" ); document.write( "9L+9B=324 FROM EQN 1 (MUTIPLIED BY 9)
\n" ); document.write( "Adding 16L=336
\n" ); document.write( "L=336/16=21
\n" ); document.write( "B=36-21=15\r
\n" ); document.write( "\n" ); document.write( "So answer : Length = 21 and width=15
\n" ); document.write( "Verification\r
\n" ); document.write( "\n" ); document.write( "add 6 to both
\n" ); document.write( "L:B=21+6:15+6
\n" ); document.write( "L:B=27:21
\n" ); document.write( "L:B=9:7
\n" ); document.write( "Okay
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