document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=134475>Question 134475</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Bill had 8600.00 in a savings account on April 1. He then deposited 800.00 on May 5 and an additional 350.00 on June 20. Find the balance in the account on July 1 if the accounts pays 4% compunded coninuosly.\r<BR>\n" );
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document.write( "I am really stuck on this one. Please help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #98372 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=98372\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> you need to use the continuous compounding formula [A=Pe^(rt)] 3 times; and then sum the results\r<BR>\n" );
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document.write( "a) P=8600 __ t=91/365\r<BR>\n" );
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document.write( "b) P=800 __ t=57/365\r<BR>\n" );
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document.write( "c) P=350 __ t=11/365 </SPAN>\n" );
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