document.write( "Question 134473: b. Suppose that an object is 100 pounds when it is at sea level. Find the value of C that makes the equation true. (Sea level is 3,963 miles from the center of the earth.) w=Cr^-2(r=distance)
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #98368 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"W=Cr%5E%28-2%29\" Start with the given equation\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"W=C%281%2Fr%5E2%29\" Rewrite \"r%5E%28-2%29\" as \"1%2Fr%5E2\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"W=C%2Fr%5E2\" Multiply\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"100=C%2F3963%5E2\" Plug in \"W=100\" (this is the given weight) and \"r=3963\" (this is the given distance from the center)\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"100=C%2F15705369\" Square 3,963 to get 15,705,369\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"100%2A15705369=C\" Multiply both sides by 15,705,369\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"1570536900=C\" Multiply\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So the constant is \"C=1570536900\"
\n" ); document.write( "
\n" );